y^2 \cdot y - 7y^2 + 10y = 0 \Rightarrow y^3 - 7y^2 + 10y = 0 \Rightarrow y(y^2 - 7y + 10) = 0 - Londonproperty
Understanding the Equation: Solving y²·y – 7y² + 10y = 0 and Factorization
Understanding the Equation: Solving y²·y – 7y² + 10y = 0 and Factorization
When solving polynomial equations, breaking them down step by step is essential for clarity and accuracy. One such equation often discussed in algebra is:
y²·y – 7y² + 10y = 0
Understanding the Context
At first glance, this may seem daunting, but simplifying and factoring reveals its underlying structure. Let’s explore how this equation transforms and how to solve it efficiently.
Step 1: Simplify the Equation
The expression starts with:
Key Insights
y²·y – 7y² + 10y
Recall that multiplying y² by y gives:
y³ – 7y² + 10y
Thus, the equation simplifies to:
y³ – 7y² + 10y = 0
This is a cubic equation that can be solved using factoring techniques.
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Step 2: Factor Out the Common Term
Notice that every term contains at least one factor of y. Factoring out y gives:
y(y² – 7y + 10) = 0
This step is crucial because it reduces the problem from solving a cubic to solving a quadratic equation inside parentheses, which is much simpler.
Step 3: Factor the Quadratic Expression
Now consider the quadratic:
y² – 7y + 10
We seek two numbers that multiply to 10 and add to –7. These numbers are –5 and –2.
Therefore:
y² – 7y + 10 = (y – 5)(y – 2)
