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Home » v_y = v \cdot \sin(\theta) = 30 \cdot \sin(30^\circ) = 30 \cdot 0.5 = 15 \, \textm/s - Londonproperty

v_y = v \cdot \sin(\theta) = 30 \cdot \sin(30^\circ) = 30 \cdot 0.5 = 15 \, \textm/s - Londonproperty

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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So, \( a_6 = 3 \cdot 2^{6-1} = 3 \cdot 32 = 96 \).
Evaluate the integral \( \int (3x^2 - 2x + 1) \, dx \).
Integral of \( 3x^2 \) is \( x^3 \).
Integral of \( -2x \) is \( -x^2 \).
Integral of \( 1 \) is \( x \).
So, \( \int (3x^2 - 2x + 1) \, dx = x^3 - x^2 + x + C \), where \( C \...
#### \( x^3 - x^2 + x + C \)1.
If a train travels 60 miles per hour for 3 hours, then slows down to 4...
The train travels 60 miles/hour * 3 hours = <<60*3=180>>180 miles in t...
It then travels 40 miles/hour * 2 hours = <<40*2=80>>80 miles in the s...

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New dimensions: (150 + 2x) m by (80 + 2x) m
New area: (150 + 2x)(80 + 2x) = 15,000 m²
Solving: 12,000 + 460x + 4x² = 15,000
4x² + 460x - 3,000 = 0
Using the quadratic formula: \( x = \frac{-460 \pm \sqrt{460^2 - 4 \ti...
\( x = \frac{-460 \pm \sqrt{211,600 + 48,000}}{8} \)
\( x = \frac{-460 \pm \sqrt{259,600}}{8} \)
\( x = \frac{-460 \pm 509.5}{8} \)
\( x = \frac{49.5}{8} = 6.1875 \)
#### 6.1875

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