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Home » The cross-sectional area of the cylinder is \(\pi (3)^2 = 9\pi\). - Londonproperty

The cross-sectional area of the cylinder is \(\pi (3)^2 = 9\pi\). - Londonproperty

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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E'(t) = \frac{d}{dt}(-t^3 + 9t^2 - 24t + 20) = -3t^2 + 18t - 24
Set \( E'(t) = 0 \) to find critical points:
-3t^2 + 18t - 24 = 0
Divide through by \(-3\):
t^2 - 6t + 8 = 0
Factor:
So, \( t = 2 \) or \( t = 4 \).
Thus, the times when the rate of change of efficiency is zero are \(\b...
Question:** Find the cubic polynomial \( f(x) \) such that \( f(-1) =...
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