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Home » Denominator zero: $ x - 2 = 0 \Rightarrow x = 2 $. - Londonproperty

Denominator zero: $ x - 2 = 0 \Rightarrow x = 2 $. - Londonproperty

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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Solution: To find the area of the region enclosed by the circle \(x^2...
x^2 + (x + 2)^2 = 16
x^2 + x^2 + 4x + 4 = 16
2x^2 + 4x + 4 - 16 = 0
2x^2 + 4x - 12 = 0
x^2 + 2x - 6 = 0
x = rac{-2 \pm \sqrt{4 + 24}}{2} = rac{-2 \pm \sqrt{28}}{2} = rac{-...
The corresponding \(y\)-coordinates are \(y = x + 2\), so:
y = (-1 + \sqrt{7}) + 2 = 1 + \sqrt{7}, \quad y = (-1 - \sqrt{7}) + 2...
The points of intersection are \(A = (-1 + \sqrt{7}, 1 + \sqrt{7})\) a...

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