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📅 March 14, 2026 👤 scraface

Mar 14, 2026

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But better: if 1 register = 20 digits = 200 bits = 25 bytes, then 10 r...
Improved system: 16 registers × 2 bytes each = <<16*2=32>>32 bytes
Difference: 250 – 32 = <<250-32=218>>218 bytes
But question asks how many bytes the ENIAC uses — assuming phrased as...
Use: 20 digits ≈ 20 × 4 = 80 bits per register → 8 bytes
registers → 10 × 8 = 80 bytes per register? Too high.
Better standard approximation: 1 digit ≈ 4 bits → 20 digits = 80 bits...
binary registers at 2 bytes each: 16 × 2 = 32 bytes
Difference: 100 – 32 = <<100-32=68>>68 bytes more in ENIAC
But the question asks: how many total bytes does the ENIAC register me...

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