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Home » 7k \equiv 1 \pmod13 - Londonproperty

7k \equiv 1 \pmod13 - Londonproperty

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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\sin(2z) = \sin(540^\circ) = 0, \quad \cos(z) = \cos(270^\circ) = 0 \R...
So even though $\sin z
e 1/2$, the $\cos z = 0$ makes the whole expression zero. But our fact...
$\cos z = 0$ â $z = 90^\circ, 270^\circ$.
$\sin z = 1/2$ â $z = 30^\circ, 150^\circ$.
All four satisfy the equation.
Thus, the solutions are $30^\circ, 90^\circ, 150^\circ, 270^\circ$.
Question: Compute $(\cos 15^\circ + i \sin 15^\circ)^6$ and express th...
Solution: By De Moivre's Theorem:
oxed{i}Question: What is the smallest positive integer whose cube end...

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