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13 going on 30 dress - Londonproperty

📅 March 13, 2026 👤 scraface

Mar 13, 2026

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📌 A = r(a + b + c - c) = r(a + b - c) + rc? \quad \text{(Not helpful directly)}

📌 Instead, recall a known formula for a right triangle:

📌 Also, area \(A = r s\), so:

📌 \frac{A}{r^2} = \frac{s}{r} = \frac{\frac{a + b + c}{2}}{\frac{a + b - c}{2}} = \frac{a + b + c}{a + b - c}

📌 Now, write in terms of \(c\). Use the identity:

📌 Let \(a + b = s_1\), but instead, use the known result:

📌 From \(r = \frac{a + b - c}{2}\) and \(A = \frac{1}{2}ab\), but better: use the known identity:

📌 A = \frac{c^2}{8} + r(a + b - c)? \quad \text{No.}

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