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#### 6, 7 or -7, -6 - Londonproperty

📅 March 14, 2026 👤 scraface

Mar 14, 2026

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h(2) = 2(2) + 1 = 5
Final answer: $\boxed{5}$
Question: A sequence of five real numbers forms an arithmetic progress...
Solution: The terms are $a$, $a + d$, $a + 2d$, $a + 3d$, $a + 4d$.
$a + (a + 2d) = 14$ → $2a + 2d = 14$ → $a + d = 7$
$a + d = 5$
But $a + d = 7$ from (1) and $a + d = 5$ from (2) is a contradiction....
But $a + d = 5$ and $a + d = 7$ is impossible. Therefore, no such sequ...
Wait: The second term is $a + d = 5$, and $a + (a + 2d) = 14$ → $2a +...
Contradiction: $a + d = 5$ and $a + d = 7$ cannot both hold. Thus, no...

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